The problem statement provides a string s
and requires us to find the minimum length of a palindrome that can be obtained by removing characters from the ends of the string. This essentially means finding the length of the longest palindrome prefix and suffix of the string.
Approach and Solution
The given Java solution provides a concise and efficient approach to solve the problem. Let’s break down the solution step by step:
- Convert the string
s
into a character arrayc
to enable easy manipulation of characters. - Initialize two pointers
left
andright
at the beginning and end of the string respectively. - Iterate through the string using a while loop until
left
is less thanright
. Within the loop:- Store the character at the
left
pointer in a temporary variabletemp
. - If the characters at the
left
andright
pointers are not equal, break out of the loop since the current substring is not a palindrome. - Increment
left
until it reaches a character different fromtemp
. - Decrement
right
until it reaches a character different fromtemp
.
- Store the character at the
- Return the length of the palindrome substring, which is
(right - left + 1)
. If the length is less than or equal to zero, return 0 since no palindrome substring exists.
class Solution {
public int minimumLength(String s) {
char c[] = s.toCharArray();
int left = 0, right = c.length-1;
while (left < right) {
char temp = c[left];
if (c[left] != c[right]) {
break;
}
while(left <= right && temp == c[left]) {
left++;
}
while(left <= right && temp == c[right]){
right--;
}
}
return right-left+1 <= 0 ? 0 : right-left+1;
}
}
https://leetcode.com/problems/minimum-length-of-string-after-deleting-similar-ends/
Conclusion
In this article, we explored the problem of finding the minimum length of a palindrome substring in a given string. We presented a Java solution that efficiently solves the problem by iterating through the string and identifying the longest palindrome prefix and suffix. This solution offers an elegant approach to tackle similar problems involving string manipulation and pattern recognition.