it's not about being the best it's about being better than yesterday
Introduction: The problem involves identifying pairs of indices in an array that satisfy certain conditions, with a specific mathematical operation. This blog will discuss the problem, the provided solution, and break down the code for a better understanding. Problem Overview: The goal is to find the count of such nice pairs of indices. Due to…
Efficiency is key when it comes to managing multiple jobs with varying start times, end times, and profits. In such scenarios, making the right choices can lead to a significant increase in overall profit. This is where dynamic programming comes to the rescue. In this blog, we’ll explore a Java solution that optimizes job scheduling…
Given an integer array nums and an integer k, return the k most frequent elements. You may return the answer in any order. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Constraints: 1 <= nums.length <= 105 -104 <= nums[i] <= 104 k is in the range [1, the number…
Understanding the Problem The problem statement is as follows: Given an array of words, return the k most frequent words. If there are multiple answers, return answers in their lexicographical order The Code We’ll break down the code into sections to understand how it works. Custom Data Structure: Frequency First, we define a custom class called…
Problem Statement To be frank, as I read the problem I realized it is a BFS problem. Let’s see what was my thought, we have to count the number of steps to reach the final string, this denotes we have to traverse the intermediate nodes. We cannot directly jump to the final string and apply…